Board | SCERT, Kerala |
Text Book | SCERT Based |
Class | SSLC |
Subject | Chemistry Solution |
Chapter | Chapter 2 |
Chapter Name | Gas Laws Mole Concept |
Category | Kerala SSLC |
Kerala Syllabus SSLC Class 10 Chemistry Textbook Solution Chapter 2 Gas Laws Mole Concept
- Chapter 1: Periodic Table and Electronic Configuration
- Chapter 2: Gas Laws Mole Concept
- Chapter 3: Reactivity Series and Electrochemistry
- Chapter 4: Production of Metals
- Chapter 5: Compounds of Non-Metals
- Chapter 6: Nomenclature of Organic Compounds and Isomerism
- Chapter 7: Chemical Reactions of Organic Compounds
SSLC Chemistry Part I
SSLC Chemistry Part II
Chapter 2 Gas Laws Mole Concept Textbook Solution
Let us Assess
Examine the data given in the table(Temperature and number of molecules of the gas are kept constant).
Pressure (P) | Volume (V) |
1 atm | 8 L |
2 atm | 4 L |
4 atm | 2 L |
a) calculate PxV.
b) Which is the gas law realated to this?
- Answer)
a) 8
b) Boyle's Law
Analyse the situations which given below and explain the gas law associated with it.
a) A balloon is being inflated.
b) When an inflated balloon is immersed in water, its size decreases.
- Answer)
a) Avagadros Law
b) Boyle's Law
Certain data regarding various gases kept under the same conditions of temperature and pressure are given below.
Gas | Volume (L) | No.of molecules |
Nitrogen | 10 L | x |
Oxygen | 5 L | |
Ammonia | 10 L | |
Carbon di oxide | 2x |
a) Complete the table.
b) Which gas law is applicable here?
- Answer)
a)
Gas
Volume (L)
No.of molecules
Nitrogen 10 L x Oxygen 5 L x/2 Ammonia 10 L x Carbon di oxide 20 L 2x b) Avagadros Law
a) Calculate the mass of 112L CO2 gas kept at STP ( molecular mass = 44).
b) how many molecules of CO2 are present in it?
- Answer)
a) 112 L = 112/22.4
= 5 mole
Mass of 5 mole= 5GMM=5 x 44g= 220g
b) 5 x 6.022 x 1023
Calculate the volume of 170g of ammonia at STP? (Molecular mass - 17)
- Answer)
170g NH3 = 170/17
=10 mol
Volume of 10 mol NH3 =10 x 22.4 = 224 L
Find out the number of moles of molecules present in the sample given below.
(GMM-N2 = 28g, H2O = 18g)
a) 56g N2
b)90g H20
- Answer)
a) 56/28 = 2 mol
b) 90/18 = 5 mol
The molecular mass of ammonia is 17.
a) How much is the GMM of ammonia ?
b) Find out the number of moles of molecules present in 170g of ammonia.
c) Calculate the number of ammonia molecules present in the above sample of ammonia ?
- Answer)
a) 17g
b) 170/10 = 10 mol
c) 10 x 6.022 x 1023
The molecular mass of oxygen is 32.
a) What is the GMM of O2 ?
b) How many moles of molecules are there in 64g of oxygen? How many molecules are there in it?
c) Calculate the number of oxygen atoms present in 64g of oxygen?
- Answer)
a) 32 g
b) 2 mol , 2 x 6.022 x 1023
c) 4 x 6.022 x 1023
SSLC Chemistry Textbook Solution
- Chapter 1: Periodic Table and Electronic Configuration
- Chapter 2: Gas Laws Mole Concept
- Chapter 3: Reactivity Series and Electrochemistry
- Chapter 4: Production of Metals
- Chapter 5: Compounds of Non-Metals
- Chapter 6: Nomenclature of Organic Compounds and Isomerism
- Chapter 7: Chemical Reactions of Organic Compounds
SSLC Chemistry Part I
SSLC Chemistry Part II
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