The solutions for the Trigonometric Functions are not readily available. While many schools may have a ready-made solution for this set in their school textbook, some might not. This is where our solution will be useful. In this article, you will find detailed solutions provided by us for the above set.Trigonometric Functions (Key Concept Reference) describes some basic and advanced uses of trigonometric functions, including identities, graph transformations, inverse functions, solutions of triangles, and polar coordinates.
Ncert Plus one Maths chapter-wise textbook solution for chapter 3 Trigonometric Functions Exercise 3.1. It contains detailed solutions for each question which have prepared by expert teachers to make each answer easily understand the students. they are well arranged solutions so that students would be able to understand easily.
| Board | SCERT, Kerala |
| Text Book | NCERT Based |
| Class | Plus One |
| Subject | Math's Textbook Solution |
| Chapter | Chapter 3 |
| Exercise | Miscellaneous |
| Chapter Name | Trigonometric Functions |
| Category | Plus One Kerala |
Kerala Syllabus Plus One Math's Textbook Solution Chapter 3 Trigonometric Functions Miscellaneous Exercises
Chapter 3 Trigonometric Functions Textbook Solution
Chapter 3 Trigonometric Functions Miscellaneous Exercise
Prove that: 
L.H.S.
= 0 = R.H.S
Prove that: (sin 3x + sin x) sin x + (cos 3x – cos x) cos x = 0
L.H.S.
= (sin 3x + sin x) sin x + (cos 3x – cos x) cos x
= RH.S.
Prove that: 
L.H.S. = 
Prove that: 
L.H.S. = 
Prove that: 
It is known that
.
∴L.H.S. = 
Prove that: 
numerator=(sin7x+sin5x)+(sin9x+sin3x)
=2sin(12x/2)cos(2x/2)+2sin(12x/2)cos(6x/2) (sinA+sinB=2sin(A+B)/2 cos(A-B)/2 )
=2sin6x cosx+2sin6x cos3x
=2sin6x(cosx+cos3x)
=2sin6x(2cos(4x/2)cos(2x/2)) (cosA+cosB=2cos(A+B)/2 cos(A-B)/2)
=4sin6x cos2x cosx
denominator=(cos7x + cos5x)+(cos9x+cos3x) (cosA+cosB=2cos(A+B)/2 cos(A-B)/2)
=2cos(12x/2)cos(2x/2)+2cOs(12X/2)Cos(6X/2)
=2cos6x cosx +2cos6x cos3x
=2cos6x(cosx+cos3x)
=2cos6x * 2cos(4x/2)cos(2x/2)
=4cos6x cos2x cosx
LHS=(4sin6x cos2x cosx)/(4cos6x cos2x cosx)
=sin6x/cos6x
=tan6x
Prove that: 
L.H.S. = 
, x in quadrant II
Here, x is in quadrant II.
i.e.,
Therefore, 
are all positive.
As x is in quadrant II, cosx is negative.
∴
Thus, the respective values of are
.
Find
for 
, x in quadrant III
Here, x is in quadrant III.
Therefore, 
and 
are negative, whereas
is positive.
Now, 
Thus, the respective values of 
are
.
Question 10:
Find
for 
, x in quadrant II
Here, x is in quadrant II.
Therefore,
, and 
are all positive.
[cosx is negative in quadrant II]
Thus, the respective values of
are 
.
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Chapter 3 Trigonometric Functions Miscellaneous Solution
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Plus One Math's Chapter Wise Textbook Solution PDF Download
- Chapter 1: Sets
- Chapter 2: Relations and Functions
- Chapter 3: Trigonometric Functions
- Chapter 4: Principle of Mathematical Induction
- Chapter 5: Complex Numbers and Quadratic Equations
- Chapter 6: Linear Inequalities
- Chapter 7: Permutation and Combinations
- Chapter 8: Binomial Theorem
- Chapter 9: Sequences and Series
- Chapter 10: Straight Lines
- Chapter 11: Conic Sections
- Chapter 12: Introduction to Three Dimensional Geometry
- Chapter 13: Limits and Derivatives
- Chapter 14: Mathematical Reasoning
- Chapter 15: Statistics
- Chapter 16: Probability
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